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  2. Kinematics of Machines

    Hello sir, i need an PDF or PPT files about Kinematics of Machines to Study for the both Z-Kinematics and U-Kinematics. If Possibles please share the files through Mail Mail id :kabilmech66@gmail.com Thank you Best regards....
  3. See the how calculate volumes in WebCalc - http://webcalc.com.br
  4. Indexing machine

    WebCalc provides useful online applications in various areas of knowledge, such as Mathematics, Engineering, Physics, Finance. http://webcalc.com.br
  5. cylinder volume, V(mm3)=(3.14/4)*D^2*L D= inside diameter of cylinder, mm L = length of cylinder, mm Accurate calculations: piston displacement + swept volume
  6. 2min survey for Mechanical Engineers!

    Please spend 2 minutes to fill out a short survey about your responsibilities in ordering industrial services and products for your business, employer. Follow this link! https://www.surveymonkey.com/r/7CL6SW6 Thank you!
  7. CAD CAM ENGINEER

    Which Are The Top Websites That Every Mechanical Engineer Should Know ? Please let me know.
  8. compressibility factor

    How the compressibility factor is related to mach number how it is derived?? please explain.
  9. Sheet Metal Bending: stuck on calculating the minimum radius required up vote 0 down vote favorite I have the following parameters: Density, Elastic Modulus, Yield Stress, Ultimate Tension Stress, Thickness. And I'm used to calculate the minimum radius required for a bending operation on an aluminum sheet. I have already learned about the following formulas: - R = 1/k - K(y) = e(y) / (h/2) - e(y) = k.y Given that R = 1/K, the next step is to find the maximum curvature K. The problem is that I don't know how to find the K max, and I'm still stuck. Any thoughts?
  10. ======================================================================== Adapted from: Kinematics and Dynamics of Machinery by Robert L. Norton. ======================================================================== Download the much better formatted .PDF version from here: LINK ======================================================================== At times the designer would like to design a mechanism that would have to go through three positions. In this case the designer would start with the required three positions of the coupler and would work his way to decide on the location of the two pivot points for the ground link. The location of the two pivot points is not the result of the designer’s choice, but is decided by the geometry of the three positions required. This is not practical; often times the designer is constrained to work with specific pivot points to form the ground link while still achieving the required three positions by the coupler motion. This article discusses one of the simplest methods to go about doing that. Let’s talk a look at this problem: Figure1: Problem Statement Design fourbar linkage to move the link CD shown between the positions C1D1 to C2D2 and then to C3D3. Use specified fixed pivots O2 and O4. The first thing we need to do is to “invert” the problem. The way to do this is to think about the coupler (C1D1) as the ground instead and the ground (O2O4) as the coupler. For now we have one ground, (C1D1), and we have only one position for the coupler (O2O4). We are going to find two more positions for the now coupler (O2O4) that would correspond to the two other positions (C2D2). To do this we need to define the relation between The coupler and the ground. Draw construction arcs from point C2 to O2 and from point D2 to O2 whose Radii define the sides of triangle C2O2D2. This defines the relationship of the fixed pivot O2 to the coupler line CD in the second coupler position. Draw construction arcs from C2 to O4 and from point D2 to O4 to define the triangle C2O4D2. This defines the relationship of the fixed pivot O4 to the coupler line CD in the second position. After locking the relative location of O2O4 in relation to the second position C2D2, it is time to slide this ground, now coupler, to its new location as if it wasn’t the ground but the coupler. That’s to say, we are trying to answer the question: if C1D1 is the ground, where would the coupler, O2O4, be in the second position? You can imagine this happening by sliding the triangle along the two lines C2C1 and D2D1. This results in a new position for O2’O4’. By doing this, we have pretended that the ground link moved from O2O4 to O2’O4’ instead of the coupler moving from C1D2 to C2D2. We have effectively inverted the problem. Now we have two positions for the now coupler, O2O4; O2O4 and O2’O4’. We need another third position to correspond with the third position C3D3. To do this, we need to repeat the same process again by defining the relation of the link O2O4 in relation to C3D3 after that we need to shift it back to C1D1 as if the link O2O4 was the coupler not the ground. Performing this will result in the third position O2’’O4’’. This is the relative location of the link O2O4 in its third position as a coupler in relation to the new ground link C1D1. Now we have three positions for the pretended coupler O2O4. O2O4, O2’O4’ and O2’’O4’’ Right now the problem is fully redefined; we have three positions for the newly decided coupler O2O4 and the link CD in the first location C1D1. We can now rename those three positions O2O4, O2’O4’ and O2’’O4’’ to E1F1, E2F2 and E3F3. We can now deal with the three positions as we would normally solve for three position coupler problem. First we need to draw the lines E1E2 and E2E3. Then we have to draw the perpendicular bisectors of these lines. The bisectors will intersect in point G. We repeat the same process for point F; draw lines F1F2 and F2F3 then draw the perpendicular bisector of these lines. These two bisectors will intersect in point H. Now we have a fourbar linkage, GEFH, in which the coupler, EF, goes through three positions. If you recall, EF is not actually our coupler. EF represents our ground O2O4. What we need to do now is to re-invert the problem again to its original form. By switching EF to be the ground link and GH to be the coupler link we reach at this linkage. Now we have our coupler, link GH, that should be connected back to the first position that we wish to achieve; C1D1. By extending link 3, GH, to reach to C1D1 we form our final mechanism that guides the coupler, link 3 (HGCD) through the three required positions. The final thing we need to do is to add a driver Dyad to drive the link O4H. This is simply done by treating O4H as rocker in a crank rocker design problem. The rocker, now O4H, has to pass through H2 and H3 to result in the required motion. Afterwards, the final mechanism is checked for toggle positions and that it can reach the required positions smoothly and in orderly fashion. In conclusion, the designer is not limited to the resulting fixed pivots for the solution of three positions coupler problems. By using the illustrated method, the design can specify the required fixed pivots and the required coupler motion and work his way around to getting those two requirements achieved. Adapted from: Kinematics and Dynamics of Machinery by Robert L. Norton.
  11. Volume of cylinder is area of circle X height of cylinder =3.14Xradius Xradius Xh
  12. To,
    3rd Nov.. 2017.

                 Subject : Regarding Job,B.E Mechanica

    Respected Sir,

         I am Sneh Shah, A Mechanical  engineer completed B.E. MECHANICAL
    ENGINEER-2017.
         I am Apply for MECHANICAL regarding Job.It will be pleasure for me to work
    with the company's experienced employees &  this will enhance  my
    industrial experience  & technical  knowledge.
         I assure you that if I get an opportunity  to work with the
    company,  I will work with my full sincerity &  dedication.
         For your  reference here I am attaching  my resume.

    Thank you.

    Awaiting  for your early response...

    Yours Sincerely,

    Sneh J. Shah

    my Resume.pdf

  13. LightSail Energy

    LightSail Energy is one of the most eminent startups that hails from Silicon Valley founded by Danielle Fong, Steve Crane, and Ed Berlin in 2009. LightSail Energy has the concept of low-cost grid-scale energy storage solution in order to optimise power grids, democratizing access to energy and adhere on sustainable development. Investors such as Khosla Ventures, Innovacorp, Triple Point Capital, Peter Thiel, Bill Gates have invested in LightSail Energy. LightSail Energy produces one of the world cleanest and economical storage systems.The website of the startup is http://www.lightsail.com/ They have designed an excellent method of capturing heat energy and regenerating useful energy from compressing air. The process involves injecting fine, a dense mist of water spray which rapidly absorbs heat energy of compression and provides it during expansion. The system is fully reversible. To store energy, the system draws electricity from the grid and converts it into compressed air and heat. To deliver energy, compressed air and heat are turned back into electricity using the same system. The system has 300+ hours of operation, 10 degrees Celcius temperature difference, 1000 rpm reciprocating piston compressor/expander and 250 KW highest power achieved. For low-cost storage, air is packed in a convenient shipping container and for large storage, underground caverns are used. This way of storing energy could be helpful in transforming intermittent wind and solar power into baseload energy.
  14. One of the best guider i saw

  15. Indexing machine

    how to calculate gear ratios for cutting a slot with pitch of 19.68 metre on a 85 mm diameter shaft
  16. how to cut a narrow slot on shaft of diameter 85mm having a pitch of 19.68 metre using indexing head
  17. Manufacturing Processes

    I am conducting a research study on the knowledge of manufacturing processes, from traditional casting to latest additive manufacturing among engineers. I shall appreciate if you could spare few minutes of your valuable time to complete the questionnaire (link below) which would help me on my Engineering Product Design research.https://goo.gl/ApCcHBThank you in advance.
  18. This project is truly commendable.
  19. Stronger or Stiffer ?

    When considering any loading condition, bending moment, axial loading, and torsional loading, all contribute to the stress analysis of the particular section. It is important to do your best to identify those loads before you begin your analysis. This is a sample of some analysis I did many years ago. It shows the sections of this cast steel section that were important to the analysis. Please take a look at this link: https://fought-engineering-consulting.com/2012/05/05/strain-gages-and-the-mechanical-engineer/ It discusses strain gage work, and determining what the expected stresses will be under load.
  20. Halloween is here so I thought I would post a project I worked on a few years back, enjoy. IMG_0494.MOV
  21. One of the best posts read so far for developing good habits #MustRead :)

    https://www.developgoodhabits.com/good-daily-habits-list/

     https://www.

  22. Service of servo ATC for  turning centre.

     

    IMG_20170728_151341.jpg

  23. Stronger or Stiffer ?

    Also remember it will be stronger in bending but not in tension.
  24. Learn as many as you can. Each employer you work for may have a different CAD package. The more you know the easier it is to get employment.
  25. DET

    SK.CV.doc
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