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Mechanical Engineering

tooldtocare

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  1. Science students need a problem too solve. A machine that claims to produce useful energy while defying logic. Students are to evaluate the physical properties showing why the design is flawed. Pickout the flaw you see and write a summary of what is technically wrong in your own words. As a student you can pick out where he/she sees flaws in the design/physical properties that prevents the machine from operating as advertised. The forum body will grade the papers as presented. It is now, where I live Wednesday, March 31, 2021 @ 12:00AM cst usa The final submittals must be posted here no latter than July 4, 2025. Discussions on submittals end on January 1, 2026 Students; attached is the machine, SeaEngine detail its flawsSEAPOWER.pdf
  2. Can we then agree that a cubic foot of sea water weighs 67 lbs. It takes a force of 67 pounds on an empty cube to submerge the cube from surface to one (1) foot deep into the water. Do we agree-? Can you convert a constant force of 118,428 pounds of force traveling at 3 feet per second-? Unfortunately, this is nowhere near enough information for you to go on - I understand - but hopefully it is a start in the right direction. Thanks, I enjoyed your thoughts, again thanks, May you and yours have a great day and beyond. I gave you my company email address. if you sent anything my spam blocker may have bounced your address. If so, sorry I will try to fix it If not, ignore, continue on
  3. In the human context of things emotions drives the human ability to dream the impossible dream. Unfortunately, this takes us further away from the OP
  4. I totally disagree with your statement Finance is based on emotions and psychology Finance is based on numbers not human emotions.
  5. As a side note: Machine an apparatus using or applying mechanical power and having several parts, each with a definite function and together performing a particular task. tinyurl.com/7e4v5vuk air pressure at sea level about 14.7 pounds per square inch One atmosphere (101.325 kPa or 14.7 psi) is also the pressure caused by the weight of a column of fresh water of approximately 10.3 m (33.8 ft). Thus, a diver 10.3 m underwater experiences a pressure of about 2 atmospheres (1 atm of air plus 1 atm of water). Conversely, 10.3 m is the maximum height to which water can be raised using suction under standard atmospheric conditions.
  6. Machine an apparatus using or applying mechanical power and having several parts, each with a definite function and together performing a particular task. tinyurl.com/7e4v5vuk aka: SeaEngine
  7. I came up with an idea that could possibly produce more useful energy than is required to keep the system running & no it is not a perpetual motion machine. The output is mechanical to electric and that is why I am introducing this idea here. SeaPower description Attached is a diagram that details a new energy generating power source using the expanding rise of air underwater as a lifting force. This is the same principal that keeps a boat afloat. A cubic foot of air under water has a lifting force of 67 pounds. A ship/boat that weighs 2,000 pounds must displace (2,000/67)=29.85 cubic feet of water to stay afloat. In the diagram, there is a vertical row of balloons. The lower balloon or inverted umbrella; is injected with 40,000 cubic feet of air compressed to 15 ATM resulting in a volume of 2,666.66 cubic feet of air. When the first balloon rises 99 feet to 12 ATM it will expand to 3,333.33 cubic feet As each balloon rises it will expand from 2,666.66 feet until it reaches the surface with a volume of 40,000 cubic feet. There are fifteen (15) balloons each tied together in a vertical row. The combined lifting force of the 15 balloons is 118,428 pounds of continuous lifting force. In order to maintain this lifting force, the lowest balloon must be injected with 40,000 cubic feet of air compressed to 2,666.66 cubic feet. When it rises a new balloon replaces it in a circular motion, as the diagram attached shows. Principles to run the machine [1] an enclosed container (X) of air submerged in water has a lifting force (Y) equal to the volume of the water displaced minus the weight of the container; [2] connection multiple containers one on top of the other creates a combined lifting force of (Y)+ (Y)+ (Y)+ (Y)+ (Y)+ (Y)+ (Y)+ (Y)+ (Y)+ (Y) Which is a greater lifting force than (Y) [3] the energy needed to fill one container is equal to the energy needed to sustain the combined lifting force of the 10 (ten) containers referenced above minus the energy needed to keep it running. That is why I am here. I need to calculate: [1] the electrical power of a pulling force of 118,428 foot pounds can produce. [2] the electric power needed to compress 40,000 cf down to 2,666.666 cubic feet [3] the speed of the rising balloons Comments please
  8. G B Reid, I used 3 feet per second because I read an article that stated that an air bubble in water will rise at 3 fs. Looking further into this I have discovered that it is a bit more complicated than I first thought. Since the air in the balloons are expanding as they rise the enlarging balloons will accelerate the rising speed. Based on your post, I need to convert everything into Joules but first I need to come up with a speed and from there I can work on determining if I am using more energy to keep the system running than I am getting out of it. I have a land surveying company in Austin, Texas which has nothing to do with the seaengine. I dreamed this up one night and have not been able to let it go since. As you are aware, land surveyors are not engineers or electricians and this idea is way over my pay grade. Having said that, I am willing to pay $1,000us to anyone who can take this idea, look at it and then write an epitaph for the seaengine so that I can insert it into the drawing before putting it in the dead drawer for good. Thanks for your input thomas@waterloosurveyors.com wish you and yours the best today and for evermore.
  9. I am finding the answers on this forum interesting because I posed this same discussion on an electric forum and the response I got were in mechanical terms, here in a mechanical forum the response I am getting is electrical.
  10. Thank you for your input I sincerely appreciate your response. I knew there would be losses in the efficiency of the machine but because of my limited understanding of the machine’s inner workings I could not pinpoint where these losses would come from. Having said that even with these losses the machine would still operate and produce some useful work. To calculate how much useful work the seaengine can produce a few properties need to be determined. [1] what is the speed of the rising air bubbles? [2] what is the lifting force of the rising bubbles? [3] how much energy is required to fill the lowest balloon with air? [4] other operating facts that need to be considered. I calculated that the seaengine has a combined lifting force of 118,428 pounds of lifting force. That is a static force. There is no motion involved, it is equivalent to a large weight. Questions 1-4 above need to be determined to evaluate the energy output. Personally, I am enjoying the challenges involved in determining the above regardless of the ultimate conclusion is that it will not work, end of story. why will it not work?
  11. Output of this machine attached is 118,428 pounds of lifting force moving at 33 feet per second. How can this principle be converted to electrical output?
  12. I created this topic to give others here an opportunity to do a little math to improve their skills in solving a mechanical problem. The problem is whether this machine can produce the energy claimed and whether the machine produces more energy that is consumed to operate the machine. I am 80% confident the machine produces less energy than is required to maintain the operation of the machine. Unfortunately, when I do the math, I get a positive return but that theoretically could not be true.
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