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Mechanical Engineering

Henry Kurniadi

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Henry Kurniadi last won the day on April 26

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  1. Delete the mating. Change from one type of mating to another.
  2. You need to free up the mates on other mating. Could be lessen the stringent from fixed connection to slide connection or roller connection.
  3. Everyone starts from something. Good engineers know the basics. Great engineers know both the basics and actual practices.
  4. Mike, I am pretty sure this would violate the building code. As you add loading to the roof without permission. but if you insist, this the mechanical equations. https://www.swiftcalcs.com/inline_worksheets/3812ccc2-6804-45d4-b577-2d0bc718b3ac/AISC_%231_Simple_Beam-Uniformly_Distributed_Load you get the maximum M, use stress = M c/ I and compare it with the steel I-beam strength/limit
  5. See this mate https://moldeddimensions.com/compression-and-shape-factor.php assuming the rubber not damaged Input force = output force pi x input area = po x bulging area
  6. https://energyfreakshow.com/2013/01/27/dont-insulate-your-hot-water-pipes/ In short, hot water didnot stored in pipes. New Water tanks already have proper insulation.
  7. Could be electromagnetic from solenoid. no current, no magnetic force. energized with current, solenoid produce magnetic force that move the pin laterally. google the term, solenoid actuator. Plenty of commercial product as well.
  8. Stress and deflections are primarily function of diameter. Buckling could be said combination of both diameter and thickness. Stiffness (for vibration) primarily function of diameter. Mass (and material costs) primarily function of thickness.
  9. Also, adding more pulley means that the vertical movement reduced for each additional pulley. using 1 pulley, F = W, you move F 1 m, you get W lifted for 1 m. using 2 pulley, F = W/2, you move F 1 m, you get W lifted for only 0.5 m. using 3 pulley, F = W/3, you move F 1 m, you get W lifted for only 0.333 m. But mostly, what DrD said.... friction
  10. Wait until you work for a while and realize that most the "mechanical engineers" can't grasp the basic concept of mechanics, fluid mechanics and any basic subjects of mechanical engineering. They won't bother about anything that don't involve money. But they positioned higher than you and obviously better salaried than you.
  11. Vi= 45 km/h = 12.5 m/s Vf= 0 km/h = m/s t = 0.2 sec (industrial standards) m = 5 x m_original = ... (5g thingy) Impulse F x dt = m x (Vi - Vf) Applied load F to front end of the chassis.
  12. It should be E not E^2. Other than that it looks correct. Established books make mistakes (albeit rarely). Here's for other potentially conflicting reference https://www.machinemfg.com/load-analysis-driven-power-calculation-symmetrical-3-roll-plate-bending-machine/ I've seen very rare occasion where constants do have dimensional units. (I recall a book by Niemann on Design of Machine Elements, the original German edition) Niemann & Hirt, Maschinenelemente Volume 1: Konstruktion und Berechnung von Verbindungen, Lagern, Wellen Volume 2: Getriebe allgemein, Zahnradgetriebe - Grundlagen, Stirnradgetriebe Volume 3: Schraubrad-, Kegelrad-, Schnecken-, Ketten-, Riemen-, Reibradgetriebe, Kupplungen, Bremsen, Freiläufe Never seen it in American books or European books using SI units. There are occasions that constants have dimensional units in practical standards/codes as well. But that's a different story.
  13. Can you use ur feet to write? with some practice you can. It may never be better than your hand writing, but you can have a decent feet writing.
  14. I think this problem goes to T = J x alpha = J x dw/dt But yeah, DrD is correct. Without braking torque, since dw/dt =0, this equation is lacking something.
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