- 0

## 3 answers to this question

## Recommended Posts

## Join the conversation

You can post now and register later. If you have an account, sign in now to post with your account.

- 0

You can post now and register later. If you have an account, sign in now to post with your account.

I have a problem where I'm trying to work out the axial force it takes to sharpen a pencil with a standard pencil sharpener.

I found a textbook that gives a formula to find this axial feeding force but the number seems much too high.

The answer I have currently is a thrust force of 187N. This is 19.12 kg force which if I were to stand the pencil up straight and place a 20kg weight on top, that would seem excessive to what I'm doing on the horizontal. If this the correct way of looking at it?

The formula given is below with variables as:

R = 3220 J/m^2 or 3.22kJ/m^2 (Toughness of cedar wood pencil)

r = 0.0041m (radius of pencil)

p = 23 degrees (angle of pencil)

I've been using SI units in all these variables.

## Share this post

## Link to post

## Share on other sites